In the figure, not drawn to scale, HKLM and GJMN are rhombuses. Given that ∠LKJ = 112° and ∠HGN = 124°, find
- ∠GNJ
- ∠JWH.
(a)
∠GNJ
= (180° - 124°) ÷ 2
= 56 ÷ 2
= 28° (Isosceles triangle, GN = GR)
(b)
∠JHM
= 180° - 112°
= 68° (Interior angles, LK//MQ)
∠NJG = ∠GNJ = 28° (Isosceles Lriangle, GN = GR)
∠JWH
= 180° - 68° - 28°
= 84° (Angles sum of triangle, WJQ)
Answer(s): (a) 28°; (b) 84°