In the figure, not drawn to scale, LNPQ and KMQR are rhombuses. Given that ∠PNM = 116° and ∠LKR = 124°, find
- ∠KRM
- ∠MWL.
(a)
∠KRM
= (180° - 124°) ÷ 2
= 56 ÷ 2
= 28° (Isosceles triangle, KR = KR)
(b)
∠MLQ
= 180° - 116°
= 64° (Interior angles, PN//QQ)
∠RMK = ∠KRM = 28° (Isosceles Priangle, KR = KR)
∠MWL
= 180° - 64° - 28°
= 88° (Angles sum of triangle, WMQ)
Answer(s): (a) 28°; (b) 88°