In the figure, not drawn to scale, LNPQ and KMQR are rhombuses. Given that ∠PNM = 118° and ∠LKR = 122°, find
- ∠KRM
- ∠MWL.
(a)
∠KRM
= (180° - 122°) ÷ 2
= 58 ÷ 2
= 29° (Isosceles triangle, KR = KR)
(b)
∠MLQ
= 180° - 118°
= 62° (Interior angles, PN//QQ)
∠RMK = ∠KRM = 29° (Isosceles Priangle, KR = KR)
∠MWL
= 180° - 62° - 29°
= 89° (Angles sum of triangle, WMQ)
Answer(s): (a) 29°; (b) 89°