In the figure, not drawn to scale, XZAB and WYBC are rhombuses. Given that ∠AZY = 119° and ∠XWC = 122°, find
- ∠WCY
- ∠YWX.
(a)
∠WCY
= (180° - 122°) ÷ 2
= 58 ÷ 2
= 29° (Isosceles triangle, WC = WR)
(b)
∠YXB
= 180° - 119°
= 61° (Interior angles, AZ//BQ)
∠CYW = ∠WCY = 29° (Isosceles Ariangle, WC = WR)
∠YWX
= 180° - 61° - 29°
= 90° (Angles sum of triangle, WYQ)
Answer(s): (a) 29°; (b) 90°