In the figure, not drawn to scale, GJKL and FHLM are rhombuses. Given that ∠KJH = 120° and ∠GFM = 126°, find
- ∠FMH
- ∠HWG.
(a)
∠FMH
= (180° - 126°) ÷ 2
= 54 ÷ 2
= 27° (Isosceles triangle, FM = FR)
(b)
∠HGL
= 180° - 120°
= 60° (Interior angles, KJ//LQ)
∠MHF = ∠FMH = 27° (Isosceles Kriangle, FM = FR)
∠HWG
= 180° - 60° - 27°
= 93° (Angles sum of triangle, WHQ)
Answer(s): (a) 27°; (b) 93°