In the figure, not drawn to scale, DFGH and CEHJ are rhombuses. Given that ∠GFE = 116° and ∠DCJ = 124°, find
- ∠CJE
- ∠EWD.
(a)
∠CJE
= (180° - 124°) ÷ 2
= 56 ÷ 2
= 28° (Isosceles triangle, CJ = CR)
(b)
∠EDH
= 180° - 116°
= 64° (Interior angles, GF//HQ)
∠JEC = ∠CJE = 28° (Isosceles Griangle, CJ = CR)
∠EWD
= 180° - 64° - 28°
= 88° (Angles sum of triangle, WEQ)
Answer(s): (a) 28°; (b) 88°