In the figure, not drawn to scale, ZBCD and YADE are rhombuses. Given that ∠CBA = 120° and ∠ZYE = 122°, find
- ∠YEA
- ∠AWZ.
(a)
∠YEA
= (180° - 122°) ÷ 2
= 58 ÷ 2
= 29° (Isosceles triangle, YE = YR)
(b)
∠AZD
= 180° - 120°
= 60° (Interior angles, CB//DQ)
∠EAY = ∠YEA = 29° (Isosceles Criangle, YE = YR)
∠AWZ
= 180° - 60° - 29°
= 91° (Angles sum of triangle, WAQ)
Answer(s): (a) 29°; (b) 91°