In the figure, not drawn to scale, XZAB and WYBC are rhombuses. Given that ∠AZY = 114° and ∠XWC = 124°, find
- ∠WCY
- ∠YWX.
(a)
∠WCY
= (180° - 124°) ÷ 2
= 56 ÷ 2
= 28° (Isosceles triangle, WC = WR)
(b)
∠YXB
= 180° - 114°
= 66° (Interior angles, AZ//BQ)
∠CYW = ∠WCY = 28° (Isosceles Ariangle, WC = WR)
∠YWX
= 180° - 66° - 28°
= 86° (Angles sum of triangle, WYQ)
Answer(s): (a) 28°; (b) 86°