In the figure, not drawn to scale, LNPQ and KMQR are rhombuses. Given that ∠PNM = 119° and ∠LKR = 126°, find
- ∠KRM
- ∠MWL.
(a)
∠KRM
= (180° - 126°) ÷ 2
= 54 ÷ 2
= 27° (Isosceles triangle, KR = KR)
(b)
∠MLQ
= 180° - 119°
= 61° (Interior angles, PN//QQ)
∠RMK = ∠KRM = 27° (Isosceles Priangle, KR = KR)
∠MWL
= 180° - 61° - 27°
= 92° (Angles sum of triangle, WMQ)
Answer(s): (a) 27°; (b) 92°