In the figure, not drawn to scale, WYZA and VXAB are rhombuses. Given that ∠ZYX = 115° and ∠WVB = 122°, find
- ∠VBX
- ∠XWW.
(a)
∠VBX
= (180° - 122°) ÷ 2
= 58 ÷ 2
= 29° (Isosceles triangle, VB = VR)
(b)
∠XWA
= 180° - 115°
= 65° (Interior angles, ZY//AQ)
∠BXV = ∠VBX = 29° (Isosceles Zriangle, VB = VR)
∠XWW
= 180° - 65° - 29°
= 86° (Angles sum of triangle, WXQ)
Answer(s): (a) 29°; (b) 86°