The figure is not drawn to scale. EGHJ is a trapezium and EG // JH. Given that EJ = EF, ∠JEF = 77° and ∠EGH = 102°.
- Find ∠GHJ
- Find ∠EFJ
- Find ∠FJH
(a)
∠GHJ
= 180° - 102°
= 78° (Interior angles, EG//JH)
(b)
∠EFJ
= (180° - 77°) ÷ 2
= 103° ÷ 2
= 51.5° (Isosceles triangle)
(c)
∠FJH
= ∠EFJ
= 51.5° (Alternate angles, EG//JH)
Answer(s): (a) 78°; (b) 51.5°; (c) 51.5°