The figure is not drawn to scale. JLMN is a trapezium and JL // NM. Given that JN = JK, ∠NJK = 73° and ∠JLM = 101°.
- Find ∠LMN
- Find ∠JKN
- Find ∠KNM
(a)
∠LMN
= 180° - 101°
= 79° (Interior angles, JL//NM)
(b)
∠JKN
= (180° - 73°) ÷ 2
= 107° ÷ 2
= 53.5° (Isosceles triangle)
(c)
∠KNM
= ∠JKN
= 53.5° (Alternate angles, JL//NM)
Answer(s): (a) 79°; (b) 53.5°; (c) 53.5°