The figure is not drawn to scale. JLMN is a trapezium and JL // NM. Given that JN = JK, ∠NJK = 80° and ∠JLM = 102°.
- Find ∠LMN
- Find ∠JKN
- Find ∠KNM
(a)
∠LMN
= 180° - 102°
= 78° (Interior angles, JL//NM)
(b)
∠JKN
= (180° - 80°) ÷ 2
= 100° ÷ 2
= 50° (Isosceles triangle)
(c)
∠KNM
= ∠JKN
= 50° (Alternate angles, JL//NM)
Answer(s): (a) 78°; (b) 50°; (c) 50°