The figure is not drawn to scale. CEFG is a trapezium and CE // GF. Given that CG = CD, ∠GCD = 74° and ∠CEF = 103°.
- Find ∠EFG
- Find ∠CDG
- Find ∠DGF
(a)
∠EFG
= 180° - 103°
= 77° (Interior angles, CE//GF)
(b)
∠CDG
= (180° - 74°) ÷ 2
= 106° ÷ 2
= 53° (Isosceles triangle)
(c)
∠DGF
= ∠CDG
= 53° (Alternate angles, CE//GF)
Answer(s): (a) 77°; (b) 53°; (c) 53°