The figure is not drawn to scale. FHJK is a trapezium and FH // KJ. Given that FK = FG, ∠KFG = 80° and ∠FHJ = 101°.
- Find ∠HJK
- Find ∠FGK
- Find ∠GKJ
(a)
∠HJK
= 180° - 101°
= 79° (Interior angles, FH//KJ)
(b)
∠FGK
= (180° - 80°) ÷ 2
= 100° ÷ 2
= 50° (Isosceles triangle)
(c)
∠GKJ
= ∠FGK
= 50° (Alternate angles, FH//KJ)
Answer(s): (a) 79°; (b) 50°; (c) 50°