The figure is not drawn to scale. HKLM is a trapezium and HK // ML. Given that HM = HJ, ∠MHJ = 75° and ∠HKL = 101°.
- Find ∠KLM
- Find ∠HJM
- Find ∠JML
(a)
∠KLM
= 180° - 101°
= 79° (Interior angles, HK//ML)
(b)
∠HJM
= (180° - 75°) ÷ 2
= 105° ÷ 2
= 52.5° (Isosceles triangle)
(c)
∠JML
= ∠HJM
= 52.5° (Alternate angles, HK//ML)
Answer(s): (a) 79°; (b) 52.5°; (c) 52.5°