The figure is not drawn to scale. EGHJ is a trapezium and EG // JH. Given that EJ = EF, ∠JEF = 80° and ∠EGH = 103°.
- Find ∠GHJ
- Find ∠EFJ
- Find ∠FJH
(a)
∠GHJ
= 180° - 103°
= 77° (Interior angles, EG//JH)
(b)
∠EFJ
= (180° - 80°) ÷ 2
= 100° ÷ 2
= 50° (Isosceles triangle)
(c)
∠FJH
= ∠EFJ
= 50° (Alternate angles, EG//JH)
Answer(s): (a) 77°; (b) 50°; (c) 50°