The figure is not drawn to scale. TVWX is a trapezium and TV // XW. Given that TX = TU, ∠XTU = 72° and ∠TVW = 103°.
- Find ∠VWX
- Find ∠TUX
- Find ∠UXW
(a)
∠VWX
= 180° - 103°
= 77° (Interior angles, TV//XW)
(b)
∠TUX
= (180° - 72°) ÷ 2
= 108° ÷ 2
= 54° (Isosceles triangle)
(c)
∠UXW
= ∠TUX
= 54° (Alternate angles, TV//XW)
Answer(s): (a) 77°; (b) 54°; (c) 54°