The figure is not drawn to scale. CEFG is a trapezium and CE // GF. Given that CG = CD, ∠GCD = 76° and ∠CEF = 101°.
- Find ∠EFG
- Find ∠CDG
- Find ∠DGF
(a)
∠EFG
= 180° - 101°
= 79° (Interior angles, CE//GF)
(b)
∠CDG
= (180° - 76°) ÷ 2
= 104° ÷ 2
= 52° (Isosceles triangle)
(c)
∠DGF
= ∠CDG
= 52° (Alternate angles, CE//GF)
Answer(s): (a) 79°; (b) 52°; (c) 52°