The figure is not drawn to scale. XZAB is a trapezium and XZ // BA. Given that XB = XY, ∠BXY = 76° and ∠XZA = 101°.
- Find ∠ZAB
- Find ∠XYB
- Find ∠YBA
(a)
∠ZAB
= 180° - 101°
= 79° (Interior angles, XZ//BA)
(b)
∠XYB
= (180° - 76°) ÷ 2
= 104° ÷ 2
= 52° (Isosceles triangle)
(c)
∠YBA
= ∠XYB
= 52° (Alternate angles, XZ//BA)
Answer(s): (a) 79°; (b) 52°; (c) 52°