The figure is not drawn to scale. TVWX is a trapezium and TV // XW. Given that TX = TU, ∠XTU = 77° and ∠TVW = 102°.
- Find ∠VWX
- Find ∠TUX
- Find ∠UXW
(a)
∠VWX
= 180° - 102°
= 78° (Interior angles, TV//XW)
(b)
∠TUX
= (180° - 77°) ÷ 2
= 103° ÷ 2
= 51.5° (Isosceles triangle)
(c)
∠UXW
= ∠TUX
= 51.5° (Alternate angles, TV//XW)
Answer(s): (a) 78°; (b) 51.5°; (c) 51.5°