The figure is not drawn to scale. DFGH is a trapezium and DF // HG. Given that DH = DE, ∠HDE = 80° and ∠DFG = 103°.
- Find ∠FGH
- Find ∠DEH
- Find ∠EHG
(a)
∠FGH
= 180° - 103°
= 77° (Interior angles, DF//HG)
(b)
∠DEH
= (180° - 80°) ÷ 2
= 100° ÷ 2
= 50° (Isosceles triangle)
(c)
∠EHG
= ∠DEH
= 50° (Alternate angles, DF//HG)
Answer(s): (a) 77°; (b) 50°; (c) 50°