EFGH is a quadrilateral and OEHG is a trapezium in which OE // HG and ∠FEH = 111°, ∠EHG = 120°, ∠FGH = 62° and HG = HE. Find
- ∠EFO
- ∠HEO
- ∠EGH.
(a)
∠EFO
= 360° - 120° -111° - 62°
= 67° (Sum of angles in a quadrilateral)
(b)
∠HEO
= 180° - 120°
= 60° (Interior angles, EO//HC)
(c)
∠EGH
= (180° - 120°) ÷ 2
= 60 ÷ 2
= 30° (Isosceles triangle)
Answer(s): (a) 67°; (b) 60°; (c) 30°