FGHJ is a quadrilateral and OFJH is a trapezium in which OF // JH and ∠GFJ = 113°, ∠FJH = 122°, ∠GHJ = 67° and JH = JF. Find
- ∠FGO
- ∠JFO
- ∠FHJ.
(a)
∠FGO
= 360° - 122° -113° - 67°
= 58° (Sum of angles in a quadrilateral)
(b)
∠JFO
= 180° - 122°
= 58° (Interior angles, FO//JC)
(c)
∠FHJ
= (180° - 122°) ÷ 2
= 58 ÷ 2
= 29° (Isosceles triangle)
Answer(s): (a) 58°; (b) 58°; (c) 29°