DEFG is a quadrilateral and ODGF is a trapezium in which OD // GF and ∠EDG = 107°, ∠DGF = 126°, ∠EFG = 68° and GF = GD. Find
- ∠DEO
- ∠GDO
- ∠DFG.
(a)
∠DEO
= 360° - 126° -107° - 68°
= 59° (Sum of angles in a quadrilateral)
(b)
∠GDO
= 180° - 126°
= 54° (Interior angles, DO//GC)
(c)
∠DFG
= (180° - 126°) ÷ 2
= 54 ÷ 2
= 27° (Isosceles triangle)
Answer(s): (a) 59°; (b) 54°; (c) 27°