HJKL is a quadrilateral and OHLK is a trapezium in which OH // LK and ∠JHL = 107°, ∠HLK = 126°, ∠JKL = 66° and LK = LH. Find
- ∠HJO
- ∠LHO
- ∠HKL.
(a)
∠HJO
= 360° - 126° -107° - 66°
= 61° (Sum of angles in a quadrilateral)
(b)
∠LHO
= 180° - 126°
= 54° (Interior angles, HO//LC)
(c)
∠HKL
= (180° - 126°) ÷ 2
= 54 ÷ 2
= 27° (Isosceles triangle)
Answer(s): (a) 61°; (b) 54°; (c) 27°