HJKL is a quadrilateral and OHLK is a trapezium in which OH // LK and ∠JHL = 113°, ∠HLK = 122°, ∠JKL = 65° and LK = LH. Find
- ∠HJO
- ∠LHO
- ∠HKL.
(a)
∠HJO
= 360° - 122° -113° - 65°
= 60° (Sum of angles in a quadrilateral)
(b)
∠LHO
= 180° - 122°
= 58° (Interior angles, HO//LC)
(c)
∠HKL
= (180° - 122°) ÷ 2
= 58 ÷ 2
= 29° (Isosceles triangle)
Answer(s): (a) 60°; (b) 58°; (c) 29°