PQRS is a quadrilateral and OPSR is a trapezium in which OP // SR and ∠QPS = 110°, ∠PSR = 120°, ∠QRS = 68° and SR = SP. Find
- ∠PQO
- ∠SPO
- ∠PRS.
(a)
∠PQO
= 360° - 120° -110° - 68°
= 62° (Sum of angles in a quadrilateral)
(b)
∠SPO
= 180° - 120°
= 60° (Interior angles, PO//SC)
(c)
∠PRS
= (180° - 120°) ÷ 2
= 60 ÷ 2
= 30° (Isosceles triangle)
Answer(s): (a) 62°; (b) 60°; (c) 30°