EFGH is a quadrilateral and OEHG is a trapezium in which OE // HG and ∠FEH = 107°, ∠EHG = 122°, ∠FGH = 67° and HG = HE. Find
- ∠EFO
- ∠HEO
- ∠EGH.
(a)
∠EFO
= 360° - 122° -107° - 67°
= 64° (Sum of angles in a quadrilateral)
(b)
∠HEO
= 180° - 122°
= 58° (Interior angles, EO//HC)
(c)
∠EGH
= (180° - 122°) ÷ 2
= 58 ÷ 2
= 29° (Isosceles triangle)
Answer(s): (a) 64°; (b) 58°; (c) 29°