VWXY is a quadrilateral and OVYX is a trapezium in which OV // YX and ∠WVY = 108°, ∠VYX = 122°, ∠WXY = 66° and YX = YV. Find
- ∠VWO
- ∠YVO
- ∠VXY.
(a)
∠VWO
= 360° - 122° -108° - 66°
= 64° (Sum of angles in a quadrilateral)
(b)
∠YVO
= 180° - 122°
= 58° (Interior angles, VO//YC)
(c)
∠VXY
= (180° - 122°) ÷ 2
= 58 ÷ 2
= 29° (Isosceles triangle)
Answer(s): (a) 64°; (b) 58°; (c) 29°