FGHJ is a quadrilateral and OFJH is a trapezium in which OF // JH and ∠GFJ = 112°, ∠FJH = 128°, ∠GHJ = 62° and JH = JF. Find
- ∠FGO
- ∠JFO
- ∠FHJ.
(a)
∠FGO
= 360° - 128° -112° - 62°
= 58° (Sum of angles in a quadrilateral)
(b)
∠JFO
= 180° - 128°
= 52° (Interior angles, FO//JC)
(c)
∠FHJ
= (180° - 128°) ÷ 2
= 52 ÷ 2
= 26° (Isosceles triangle)
Answer(s): (a) 58°; (b) 52°; (c) 26°