FGHJ is a quadrilateral and OFJH is a trapezium in which OF // JH and ∠GFJ = 108°, ∠FJH = 124°, ∠GHJ = 64° and JH = JF. Find
- ∠FGO
- ∠JFO
- ∠FHJ.
(a)
∠FGO
= 360° - 124° -108° - 64°
= 64° (Sum of angles in a quadrilateral)
(b)
∠JFO
= 180° - 124°
= 56° (Interior angles, FO//JC)
(c)
∠FHJ
= (180° - 124°) ÷ 2
= 56 ÷ 2
= 28° (Isosceles triangle)
Answer(s): (a) 64°; (b) 56°; (c) 28°