EFGH is a quadrilateral and OEHG is a trapezium in which OE // HG and ∠FEH = 113°, ∠EHG = 124°, ∠FGH = 65° and HG = HE. Find
- ∠EFO
- ∠HEO
- ∠EGH.
(a)
∠EFO
= 360° - 124° -113° - 65°
= 58° (Sum of angles in a quadrilateral)
(b)
∠HEO
= 180° - 124°
= 56° (Interior angles, EO//HC)
(c)
∠EGH
= (180° - 124°) ÷ 2
= 56 ÷ 2
= 28° (Isosceles triangle)
Answer(s): (a) 58°; (b) 56°; (c) 28°