NPQR is a quadrilateral and ONRQ is a trapezium in which ON // RQ and ∠PNR = 113°, ∠NRQ = 120°, ∠PQR = 62° and RQ = RN. Find
- ∠NPO
- ∠RNO
- ∠NQR.
(a)
∠NPO
= 360° - 120° -113° - 62°
= 65° (Sum of angles in a quadrilateral)
(b)
∠RNO
= 180° - 120°
= 60° (Interior angles, NO//RC)
(c)
∠NQR
= (180° - 120°) ÷ 2
= 60 ÷ 2
= 30° (Isosceles triangle)
Answer(s): (a) 65°; (b) 60°; (c) 30°