VWXY is a quadrilateral and OVYX is a trapezium in which OV // YX and ∠WVY = 109°, ∠VYX = 124°, ∠WXY = 68° and YX = YV. Find
- ∠VWO
- ∠YVO
- ∠VXY.
(a)
∠VWO
= 360° - 124° -109° - 68°
= 59° (Sum of angles in a quadrilateral)
(b)
∠YVO
= 180° - 124°
= 56° (Interior angles, VO//YC)
(c)
∠VXY
= (180° - 124°) ÷ 2
= 56 ÷ 2
= 28° (Isosceles triangle)
Answer(s): (a) 59°; (b) 56°; (c) 28°