NPQR is a quadrilateral and ONRQ is a trapezium in which ON // RQ and ∠PNR = 111°, ∠NRQ = 124°, ∠PQR = 66° and RQ = RN. Find
- ∠NPO
- ∠RNO
- ∠NQR.
(a)
∠NPO
= 360° - 124° -111° - 66°
= 59° (Sum of angles in a quadrilateral)
(b)
∠RNO
= 180° - 124°
= 56° (Interior angles, NO//RC)
(c)
∠NQR
= (180° - 124°) ÷ 2
= 56 ÷ 2
= 28° (Isosceles triangle)
Answer(s): (a) 59°; (b) 56°; (c) 28°