HJKL is a quadrilateral and OHLK is a trapezium in which OH // LK and ∠JHL = 112°, ∠HLK = 124°, ∠JKL = 68° and LK = LH. Find
- ∠HJO
- ∠LHO
- ∠HKL.
(a)
∠HJO
= 360° - 124° -112° - 68°
= 56° (Sum of angles in a quadrilateral)
(b)
∠LHO
= 180° - 124°
= 56° (Interior angles, HO//LC)
(c)
∠HKL
= (180° - 124°) ÷ 2
= 56 ÷ 2
= 28° (Isosceles triangle)
Answer(s): (a) 56°; (b) 56°; (c) 28°