The figure is not drawn to scale. Triangle JKH is an isosceles triangle. Triangle FGH is an equilateral triangle. ∠KHJ is
35 of ∠GFH and ∠GHK = ∠FHJ.
- Find ∠GHK.
- Find ∠FJH.
(a)
∠GHF = 60° (Equilateral triangle)
∠KHJ
= ∠GHF x
35 = 60° x
35 = 36°
∠GHK = ∠FHJ
∠GHK
= ∠GHF - ∠KHA) ÷ 2
= (60° - 36°) ÷ 2
= 24° ÷ 2
= 12° (Isosceles triangle)
(b)
∠FJH
= 180° - ∠GFH - ∠GHK
= 180° - 60° - 12°
= 108° (Angles sum of triangle)
Answer(s): (a) 12°; (b) 108°