The figure is not drawn to scale. Triangle GHF is an isosceles triangle. Triangle DEF is an equilateral triangle. ∠HFG is
15 of ∠EDF and ∠EFH = ∠DFG.
- Find ∠EFH.
- Find ∠DGF.
(a)
∠EFD = 60° (Equilateral triangle)
∠HFG
= ∠EFD x
15 = 60° x
15 = 12°
∠EFH = ∠DFG
∠EFH
= ∠EFD - ∠HFA) ÷ 2
= (60° - 12°) ÷ 2
= 48° ÷ 2
= 24° (Isosceles triangle)
(b)
∠DGF
= 180° - ∠EDF - ∠EFH
= 180° - 60° - 24°
= 96° (Angles sum of triangle)
Answer(s): (a) 24°; (b) 96°