The figure is not drawn to scale. Triangle HJG is an isosceles triangle. Triangle EFG is an equilateral triangle. ∠JGH is
15 of ∠FEG and ∠FGJ = ∠EGH.
- Find ∠FGJ.
- Find ∠EHG.
(a)
∠FGE = 60° (Equilateral triangle)
∠JGH
= ∠FGE x
15 = 60° x
15 = 12°
∠FGJ = ∠EGH
∠FGJ
= ∠FGE - ∠JGA) ÷ 2
= (60° - 12°) ÷ 2
= 48° ÷ 2
= 24° (Isosceles triangle)
(b)
∠EHG
= 180° - ∠FEG - ∠FGJ
= 180° - 60° - 24°
= 96° (Angles sum of triangle)
Answer(s): (a) 24°; (b) 96°