The figure is not drawn to scale. Triangle JKH is an isosceles triangle. Triangle FGH is an equilateral triangle. ∠KHJ is
25 of ∠GFH and ∠GHK = ∠FHJ.
- Find ∠GHK.
- Find ∠FJH.
(a)
∠GHF = 60° (Equilateral triangle)
∠KHJ
= ∠GHF x
25 = 60° x
25 = 24°
∠GHK = ∠FHJ
∠GHK
= ∠GHF - ∠KHA) ÷ 2
= (60° - 24°) ÷ 2
= 36° ÷ 2
= 18° (Isosceles triangle)
(b)
∠FJH
= 180° - ∠GFH - ∠GHK
= 180° - 60° - 18°
= 102° (Angles sum of triangle)
Answer(s): (a) 18°; (b) 102°