The figure is not drawn to scale. Triangle HJG is an isosceles triangle. Triangle EFG is an equilateral triangle. ∠JGH is
25 of ∠FEG and ∠FGJ = ∠EGH.
- Find ∠FGJ.
- Find ∠EHG.
(a)
∠FGE = 60° (Equilateral triangle)
∠JGH
= ∠FGE x
25 = 60° x
25 = 24°
∠FGJ = ∠EGH
∠FGJ
= ∠FGE - ∠JGA) ÷ 2
= (60° - 24°) ÷ 2
= 36° ÷ 2
= 18° (Isosceles triangle)
(b)
∠EHG
= 180° - ∠FEG - ∠FGJ
= 180° - 60° - 18°
= 102° (Angles sum of triangle)
Answer(s): (a) 18°; (b) 102°