PSLEIn the figure, ABCD is a parallelogram. AYD and YCZ are straight lines. ∠ZCD = 152°, ∠ADC = 48° and ∠ACY = 23°.
- Find ∠BCZ.
- Find ∠BAC.
(a)
∠BCD
= 180° - 48°
= 132° (Interior angles)
∠BCZ
= 360° - 152° - 132°
= 76° (Angles at a point)
(b)
∠DCY
= 180° - 152°
= 28°(Angles on a straight line)
∠BAC
= ∠ACD
= 28° + 23°
= 51° (Alternate angles)
Answer(s): (a) 76°; (b) 51°