PSLEIn the figure, EFGH is a parallelogram. ECH and CGD are straight lines. ∠DGH = 150°, ∠EHG = 47° and ∠EGC = 23°.
- Find ∠FGD.
- Find ∠FEG.
(a)
∠FGH
= 180° - 47°
= 133° (Interior angles)
∠FGD
= 360° - 150° - 133°
= 77° (Angles at a point)
(b)
∠HGC
= 180° - 150°
= 30°(Angles on a straight line)
∠FEG
= ∠EGH
= 30° + 23°
= 53° (Alternate angles)
Answer(s): (a) 77°; (b) 53°