PSLEIn the figure, HJKL is a parallelogram. HFL and FKG are straight lines. ∠GKL = 147°, ∠HLK = 47° and ∠HKF = 20°.
- Find ∠JKG.
- Find ∠JHK.
(a)
∠JKL
= 180° - 47°
= 133° (Interior angles)
∠JKG
= 360° - 147° - 133°
= 80° (Angles at a point)
(b)
∠LKF
= 180° - 147°
= 33°(Angles on a straight line)
∠JHK
= ∠HKL
= 33° + 20°
= 53° (Alternate angles)
Answer(s): (a) 80°; (b) 53°