PSLEIn the figure, KLMN is a parallelogram. KHN and HMJ are straight lines. ∠JMN = 147°, ∠KNM = 45° and ∠KMH = 20°.
- Find ∠LMJ.
- Find ∠LKM.
(a)
∠LMN
= 180° - 45°
= 135° (Interior angles)
∠LMJ
= 360° - 147° - 135°
= 78° (Angles at a point)
(b)
∠NMH
= 180° - 147°
= 33°(Angles on a straight line)
∠LKM
= ∠KMN
= 33° + 20°
= 53° (Alternate angles)
Answer(s): (a) 78°; (b) 53°