PSLEIn the figure, KLMN is a parallelogram. KHN and HMJ are straight lines. ∠JMN = 147°, ∠KNM = 42° and ∠KMH = 17°.
- Find ∠LMJ.
- Find ∠LKM.
(a)
∠LMN
= 180° - 42°
= 138° (Interior angles)
∠LMJ
= 360° - 147° - 138°
= 75° (Angles at a point)
(b)
∠NMH
= 180° - 147°
= 33°(Angles on a straight line)
∠LKM
= ∠KMN
= 33° + 17°
= 50° (Alternate angles)
Answer(s): (a) 75°; (b) 50°