PSLEIn the figure, ZABC is a parallelogram. ZXC and XBY are straight lines. ∠YBC = 153°, ∠ZCB = 47° and ∠ZBX = 22°.
- Find ∠ABY.
- Find ∠AZB.
(a)
∠ABC
= 180° - 47°
= 133° (Interior angles)
∠ABY
= 360° - 153° - 133°
= 74° (Angles at a point)
(b)
∠CBX
= 180° - 153°
= 27°(Angles on a straight line)
∠AZB
= ∠ZBC
= 27° + 22°
= 49° (Alternate angles)
Answer(s): (a) 74°; (b) 49°