PSLEIn the figure, KLMN is a parallelogram. KHN and HMJ are straight lines. ∠JMN = 151°, ∠KNM = 48° and ∠KMH = 21°.
- Find ∠LMJ.
- Find ∠LKM.
(a)
∠LMN
= 180° - 48°
= 132° (Interior angles)
∠LMJ
= 360° - 151° - 132°
= 77° (Angles at a point)
(b)
∠NMH
= 180° - 151°
= 29°(Angles on a straight line)
∠LKM
= ∠KMN
= 29° + 21°
= 50° (Alternate angles)
Answer(s): (a) 77°; (b) 50°