PSLEIn the figure, FGHJ is a parallelogram. FDJ and DHE are straight lines. ∠EHJ = 147°, ∠FJH = 43° and ∠FHD = 19°.
- Find ∠GHE.
- Find ∠GFH.
(a)
∠GHJ
= 180° - 43°
= 137° (Interior angles)
∠GHE
= 360° - 147° - 137°
= 76° (Angles at a point)
(b)
∠JHD
= 180° - 147°
= 33°(Angles on a straight line)
∠GFH
= ∠FHJ
= 33° + 19°
= 52° (Alternate angles)
Answer(s): (a) 76°; (b) 52°